1 条题解
-
0
C :
#include <stdio.h> int main() { double a,b,c; scanf("%lf",&a); scanf("%lf",&b); scanf("%lf",&c); printf("%.1lf",(a*0.2+b*0.3+c*0.5)); return 0; }C++ :
#include <bits/stdc++.h> #define int long long using namespace std; typedef long long LL; typedef pair<int,int> PII; const int MAX32=2147483647; void solve() { double a,b,c; cin>>a>>b>>c; double ans = (a*2+b*3+c*5)/10; printf("%.1lf",ans); } signed main() { // ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); int t; t=1; // cin>>t; while (t--) { solve(); } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { double low = 0; double up = 10.0; Scanner scanner = new Scanner(System.in); double A = scanner.nextDouble(); double B = scanner.nextDouble(); double C = scanner.nextDouble(); if (A >=low && A<=up && B>=low && B<=up && C>=low && C<=up) { double number = A * 0.2 + B *0.3 +C * 0.5; System.out.println(String.format("%.1f",number)); } } }
- 1
信息
- ID
- 629
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 5
- 标签
- 提交数
- 153
- 已通过
- 57
- 上传者