1 solutions
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0
C :
#include <stdio.h> int main() { int a,n; scanf("%d",&a); for(n=2;n<10000;n++){ if(n%a==2){ printf("%d\n",n); } } return 0; }C++ :
#include <iostream> using namespace std; int main() { int N; cin>> N ; for(int i=1;i<10000;i++) if(i % N == 2) cout<< i <<endl; return 0; }
- 1
Information
- ID
- 616
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 5
- Tags
- # Submissions
- 110
- Accepted
- 43
- Uploaded By