1 条题解
-
0
#include <bits/stdc++.h> using namespace std; long long to (double x) { return round (x * 1000.0); } int main() { int num = 0; double a1,b1,a2,b2,x,y; int n; cin >> a1 >> b1 >> a2 >> b2; cin >> n; a1 = to(a1); b1 = to(b1); a2 = to(a2); b2 = to(b2); while (n--) { bool xian = 0; bool mian = 0; cin >> x >> y; x = to(x),y = to(y); if (x >= min(a1,a2)&&y >= min(b1,b2)&& x <= max(a1,a2)&&y <= max(b1,b2)) mian = 1; if ( (b2-b1) * (x-a1)== (a2-a1) * (y-b1) )xian = 1; if (xian == 1 && mian == 1) { num ++; } } cout << num << "\n"; }
信息
- ID
- 1696
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 6
- 标签
- 提交数
- 141
- 已通过
- 15
- 上传者